A boy has 3 red , 2 yellow and 4 green marbles. In how many ways can the boy arrange the marbles in a line if?

Posted on March 5, 2010 by admin

A boy has 3 red , 2 yellow and 4 green marbles. In how many ways can the boy arrange the marbles in a line if all marbles of the same color are indistinguishable?

(3+2+4) ! = 9! arrangements
divide by 3! 2! 4! as the same colour marbles are not distinguishable
hnce [9! ] / [3! 2! 4!] = 1260 ways

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2 Responses to A boy has 3 red , 2 yellow and 4 green marbles. In how many ways can the boy arrange the marbles in a line if?

  1. Jimmy K says:
    March 5, 2010 at 10:29 pm

    This problem uses permutations with repetitions.

    9! / (3! * 2! * 4!) = 1260
    References :

  2. Mathematishan says:
    March 5, 2010 at 11:01 pm

    (3+2+4) ! = 9! arrangements
    divide by 3! 2! 4! as the same colour marbles are not distinguishable
    hnce [9! ] / [3! 2! 4!] = 1260 ways
    References :